The interior angles of a triangle are 60,45and 75.the shortest side is 10cm less than the longest side, determine the perimeter of the triangle to the nearest cm.include a diagram please and thank you!!

Respuesta :

Answer:

20 cm.

Step-by-step explanation:

We know that the permiter is defined as

[tex]P=L+S+M[/tex]

Where [tex]L[/tex] is the longest side, [tex]S[/tex] is the smallest and [tex]M[/tex] is the middle side.

If [tex]L=x[/tex] then, [tex]S=x-20[/tex], where we need to find an expression for [tex]M[/tex] using the law of cosines.

[tex]M^{2} =L^{2}+S^{2}-2 \times L \times S \times cos(60\°)\\M=\sqrt{x^{2}+(x-20)^{2}-x(x-20)}\\M=\sqrt{x^{2} +x^{2}-40x+400-x^{2}+20x}=\sqrt{x^{2}-20x+400}[/tex]

Replacing all expression, the perimeter is

[tex]P=x+x-20+\sqrt{x^{2}-20x+400}\\P=2x-20+\sqrt{x^{2}-20x+400}[/tex]

Using a calculator, the perimeter is 20 units centimeters.