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A potential difference of 71 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magnetic field at a speed of 6.0 m/s. The magnetic field is perpendicular to the axis of the wire.

Required:
What is the angle between the magnetic field and the wire's velocity?

Respuesta :

sarah7132012

Answer:

Explanation: please see attached file I attached the answer to your question.

Ver imagen sarah7132012

The angle between the magnetic field and the wire's velocity is 33.2 degrees.

Calculation of the angle:

Since the potential difference = 71mv = 71 *10 ^-3 V

The length is 12 cm = 0.12m

The magnetic field i.e. B = 0.27T

The speed or v = 4 m/s

here we assume [tex]\theta[/tex] be the angle

So,

e = Bvl sin[tex]\theta[/tex]

So,

[tex]Sin\theta[/tex] = e/bvl

= 71*10^-3 / 0.27 *4*0.12

= 0.5478

= 33.2 degrees

Therefore, the angle should be 33.2 degrees

Learn more about an angle here: https://brainly.com/question/14661707

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