Answer:
Option (B). Perimeter of the quadrilateral ABCD= 14.6 units
Step-by-step explanation:
From the figure attached,
Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).
Length of AB = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
= [tex]\sqrt{(3-1)^2+(5-3)^2}[/tex]
= [tex]\sqrt{8}[/tex]
= 2.83 units
Length of AD = [tex]\sqrt{(3-5)^2+(5-3)^2}[/tex]
= [tex]\sqrt{8}[/tex]
= 2.83 units
Length of BC = [tex]\sqrt{(1-3)^2+(3+1)^2}[/tex]
= [tex]\sqrt{20}[/tex]
= 4.47 units
Length of DC = [tex]\sqrt{(5-3)^2+(3+1)^2}[/tex]
= [tex]\sqrt{20}[/tex]
= 4.47 units
Perimeter of the quadrilateral = AB + AD + DC + BC
= 2.83 + 2.83 + 4.47 + 4.47
= 14.6 units
Option (B) is the answer.
