Answer:
The new pressure is 3164.58 psi.
Explanation:
We have,
Initial pressure, [tex]P_1= 2975\ psi[/tex]
Initial temperature, [tex]T_1=25^{\circ}=298.15\ K[/tex]
The tank is left in a car in the hot sun and the temperature increases to 44°C, [tex]T_2=44^{\circ} =317.15\ K[/tex]
Let [tex]P_2[/tex] is the final pressure in the tank. Gay Lussac's law,
[tex]P\propto T\\\\\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}\\\\P_2=\dfrac{P_1T_2}{T_1}[/tex]
Plugging all the values,
[tex]P_2=\dfrac{2975\times 317.15}{298.15}\\\\P_2=3164.58\ psi[/tex]
So, the new pressure is 3164.58 psi.
