Answer:
Age difference between oldest the youngest = 48 years
Step-by-step explanation:
Given: Ratio of ages of Kissi and Esinam is 3:5, ratios of ages of Esinam and Lariba is 3:5 and sum of the ages of all 3 is 147 years
To find: age difference between oldest the youngest
Solution:
Let age of Lariba be x years
As ratios of ages of Esinam and Lariba is 3:5,
Age of Esinam = [tex]\frac{3}{5}x[/tex] years
As ratio of ages of Kissi and Esinam is 3:5,
Age of Kissi = [tex](\frac{3}{5}) (\frac{3}{5}x)=\frac{9}{25}x[/tex] years
Sum of the ages of all 3 = 147 years
[tex]x+\frac{3}{5}x+\frac{9}{25}x=147\\ \frac{25x+15x+9x}{25}=147\\ x=\frac{147(25)}{49}=75[/tex]
Age of Lariba = x = 75 years
Age of Esinam = [tex]\frac{3}{5}(75)=45\,\,years[/tex]
Age of Kissi = [tex]\frac{9}{25}(75)=27\,\,years[/tex]
So,
Age difference between oldest the youngest = 75 - 27 = 48 years
