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In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m,find BC = y the unknown side

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Answer

Step-by-step explanation:

Law of sines: SinB/15 = SinA/BC

B = 90

A = 180-90-21=69°

BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m

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