Answer:
[tex]y=\dfrac{1}{2}x+\dfrac{5}{2}[/tex].
Step-by-step explanation:
If a line passing through two points, then the equation of line is
[tex](y-y_1)=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
It is given that the passing through (1,3) and (-9,-2). So, equation of line in point slope form is
[tex]\Rightarrow (y-3)=\dfrac{-2-3}{-9-1}(x-1)[/tex]
[tex]\Rightarrow (y-3)=\dfrac{1}{2}(x-1)[/tex]
Slope intercept form of a line is
[tex]y=mx+b[/tex]
where, m is slope and b is y-intercept.
Now,
[tex](y-3)=\dfrac{1}{2}(x-1)[/tex]
[tex]\Rightarrow (y-3)=\dfrac{1}{2}(x}-\dfrac{1}{2}(1)[/tex]
[tex]\Rightarrow y=\dfrac{1}{2}(x}-\dfrac{1}{2}+3[/tex]
[tex]\Rightarrow y=\dfrac{1}{2}x+\dfrac{5}{2}[/tex]
Therefore, the required equation is [tex]y=\dfrac{1}{2}x+\dfrac{5}{2}[/tex].
