what is the point-slope form of a line with slope -3 that contains the point 10, -1

Answer:
C. [tex] y + 1 = -3(x - 10) [/tex]
Step-by-step explanation:
The point-slope equation of a line:
[tex] y - y_1 = m(x - x_1) [/tex]
where m = slope, and the point is (x1, y1).
In this case, the point is (10, -1), so x1 = 10 and y1 = -1.
The slope is -3, so m = -3.
[tex] y - (-1) = -3(x - 10) [/tex]
[tex] y + 1 = -3(x - 10) [/tex]