Answer:
Final volume of the gas is 4.837mL
Explanation:
Initial volume (V1) = 350mL = 0.35L
Initial temperature (T1) = 0°C = (0 + 273.15)k = 273.15k
Initial pressure (P1) = 1.0atm
Final volume (V2) = ?
Final temperature (T2) = 10°C = (10 + 273.15)k = 283.15K
Final pressure (P2) = 75atm
To solve this question, we'll have to use combined gas equation which is the combination of all gas law I.e Charle's laws, Boyle's law, Pressure law etc.
According to combined gas equation,
(P1 × V1) / T1 = (P2 × V2) / T2
Make V2 the subject of formula,
V2 = (P1 × V1 × T2) / (P2 × T1)
V2 = (1.0 × 0.35 × 283.15) / (75 × 273.15)
V2 = 99.1025 / 20,486.25
V2 = 0.004837L
V2 = 4.837mL
The final volume of the gas is 4.837mL
Answer:
4.84mL
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial volume (V1) = 350mL
Initial temperature (T1) = 0°C
Initial pressure (P1) = 1atm
Final temperature (T2) = 10°C
Final pressure (P2) = 75atm
Final volume (V2) =...?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This can be achieved by using the formula below:
T(K) = T (°C) + 273
Initial temperature (T1) = 0°C
Initial temperature (T1) = 0°C + 273 = 273K
Final temperature (T2) = 10°C
Final temperature (T2) = 10°C + 273 = 283K
Step 3:
Determination of the new volume.
The new volume can be obtained by using the general gas equation as follow:
P1V1/T1 = P2V2/T2
1 x 350/273 = 75 x V2/283
Cross multiply
273 x 75 x V2 = 1 x 350 x 283
Divide both side by 273 x 75
V2 = (1 x 350 x 283) / (273 x 75)
V2 = 4.84mL
Therefore, the new volume is 4.84mL
