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15 POINTS!! PLEASE HELP
The equation of line WX is 2x + y = −5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)?

y = one half x + three halves
y = negative one halfx + three halves
y = one half x − three halves
y = negative one halfx − three halves

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keziakh004

Answer:

y = 1/2x - 1

Step-by-step explanation:

The easiest was you do this is to first rearrange the equation into slope-intercept form (y = mx + b).  After rearranging, you can find the slope (m).

2x + y = -5

y = -2x - 5

The slope is -2.  Since the line we are trying to find is perpendicular, find the inverse and multiply it by -1.

-2  =>  1/2

Now use the point-intercept form to find the new equation.  Use the slope (1/2) and the given point (-1, -2).

y - y₁ = m(x - x₁)

y - (-2) = 1/2(x - (-2))

y + 2 = 1/2(x + 2)

y + 2 = 1/2x + 1

y = 1/2x - 1

The equation of the line perpendicular to line WX is  y = 1/2x - 1.

The equation is y = (1/2)x -(3/2) ; y = one half x − three halves.

The correct option is D.

What is the equation of a Straight Line?

An equation of the straight line is given by y = mx+c,

Here m is the slope and c is the intercept on y-axis.

The equation of the line WX is 2x+y = -5

y = -2x -5

The product of the slopes of the line and the line perpendicular to this line will be -1

Therefore the slope of the line perpendicular to the line WX is -2 * m = -1,

m = 1/2

y = (1/2)x +c

The line passes through the points (-1, -2)

-2 = (1/2) (-1) +c

c = -2 +(1/2)

c = (-4 +1) /2

c = -3/2

Therefore, the equation is y = (1/2)x -(3/2) ; y = one half x − three halves.

The correct option is D.

To know more about Equation of Straight Line

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