Answer:
0.46 newtons
Step-by-step explanation:
For these kinds of problems, you can employ the formula
[tex]E=\dfrac{F}{q}[/tex]
where E represents the field in N/C, F represents the force in newtons, and q represents the charge in coulombs. You can therefore set up the following equation:
[tex]1.4\times 10^4 N/C=\dfrac{F}{3.25\times 10^{-5}C} \\\\[/tex]
[tex]F=(1.4\times 10^4 N/C) \times (3.25 \times 10^{-5} C)=4.6 \times 10^{-1} N[/tex] (following sig figs)
Hope this helps!
