The zero of the quadratic function f(x) = 16x2 + 32x − 9 is -2.25
We have:
f(x) = 16x^2 + 32x - 9
Next, we test the options.
x = –5.25
f(-5.25) = 16(-5.25)^2 + 32(-5.25) - 9
Evaluate
f(-5.25) = 264 --- this is false
x = –2.25
f(-2.25) = 16(-2.25)^2 + 32(-2.25) - 9
Evaluate
f(-2.25) = 0 ---- this is true
Hence, the zero of the quadratic function f(x) = 16x2 + 32x − 9 is -2.25
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