A worker pushes a wheelbarrow with a force of 20N downward and to the left, as shown in the figure below. The angle the handle makes with the horizontal is 34°. Note that the figure is not drawn to scale. Write the force vector F in the form =F+aibj. Do not round any intermediate computations, and round the values in your answer to the nearest hundredth. f=

Respuesta :

Answer:

The values of F will be "16.58 i + 11.18 j".

Step-by-step explanation:

The given values are:

Force, F = 20 N

Angle, Ф = 33°

The formula use in the given scenario will be:

⇒  [tex]x=a \ Cos\theta[/tex]

⇒  [tex]y=a \ Sin\theta[/tex]

Now,

For Force, [tex]F=ai+bj[/tex]

⇒  [tex]a=F \ Cos\theta[/tex]

⇒     [tex]=20 \ Cos(34^{\circ})[/tex]

⇒     [tex]=20\times .829[/tex]

⇒     [tex]=16.58[/tex]

and,

⇒  [tex]b=F \ Sin\theta[/tex]

⇒     [tex]=20 \ Sin(34^{\circ})[/tex]

⇒     [tex]=20\times .55[/tex]

⇒     [tex]=11.18[/tex]

So that,

⇒  [tex]F=16.58 \ i+11.18 \ j[/tex]