Answer:
2(2q+7)(3q-2)=0
Step-by-step explanation:
lets set up the equation equal to 0:
12q^2+34q-28=0
now, lets factor:
2(6q^2+17q-14)=0
now, lets find the solutions:
2q+7=0
2q=-7
q=-3.5
3q-2=0
3q=2
q=2/3
