part 1. Find the missing sides for the 30-60-90 Triangles. Please show work

1. cos(30) = a/16
a = 16 x cos(30)
a = 8√3
sin(30) = c/16
c = 16 x sin(30)
c = 8
2. cos(30) = d/28
d = 28 x cos(30)
d = 14√3
sin(30) = f/28
f = 28 x sin(30)
f = 14
3. sin(30) = x/62
x = 62 x sin(30)
x = 31
cos(30) = y/62
y = 62 x cos(30)
y = 31√3
Answer:
1. (a, c) = (8, 8√3)
2. (d, f) = (14, 14√3)
3. (x, y) = (31, 31√3)
Step-by-step explanation:
Side lengths in a 30°-60°-90° triangle have the ratios 1 : √3 : 2. You can multiply these ratio values by an appropriate constant to make them match the lengths in your triangle.
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1. a : c : 16 = 1 : √3 : 2
Multiply by 16/2 = 8:
= 8 : 8√3 : 16
a = 8, c = 8√3
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2. d : f : 28 = 1 : √3 : 2
Multiply by 28/2 = 14:
= 14 : 14√3 : 28
d = 14, f = 14√3
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3. x : y : 62 = 1 : √3 : 2
Multiply by 62/2 = 31:
= 31 : 31√3 : 62
x = 31, y = 31√3