Respuesta :
Answer: 1 mole of any gas has a volume of 22.4 L at STP
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 1
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]273K[/tex] (at STP)
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{1mol\times 0.0820 L atm/K mol\times 273K}{1atm}=22.4L[/tex]
Thus 1 mole of every gas occupies 22.4 L at STP
Answer:
1 mole of any gas has a volume of 22.4 L at STP
Explanation:
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