Respuesta :

X=3 HJ=21 JK=12 First add HJ and JK together to get 7x+12, and make it equal to KH or 33. Then solve for X and go from there.

The value of x=3, length of HJ=21 and JK=12 can be found out using Segment Addition Postulate.

What is Segment Addition Postulate?

If B is between A and B, then AB +BC = AC

Find the values of x, HJ and JK

Given that, HJ=4x+9

JK=3x+3

KH=33

According to the Segment Addition Postulate, we can say that

HJ+JK=KH

4x+9+3x+3=33

(4x+3x)+(9+3)=33

7x+12=33

7x=33-12=21

  • x=3
  • HJ=4x+9

    =4(3)+9

HJ=12+9=21

  • JK=3x+3

    =3(3)+3

JK=9+3=12

The value of x=3, length of HJ=21 and JK=12 .

Learn more about Segment Addition Postulate here:

brainly.com/question/22093187

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