Answer:
So the empirical formula is C14H18N2O5
Explanation:
C = 57.2% = 12g/mol
H = 6.1% = 1g/mol
N = 9.5% = 14g/mol
O = 27.2% = 16g/mol
Empirical Formula for compound hmm
Assume
C = 57.2g
H = 6.1g
N = 9.5g
O = 27.2g
So we have
C = 57.2g/12g = 4.76 moles
H = 6.1g/1g = 6.10 moles
N = 9.5g/14g = 0.68 moles
O = 27.2g/16g = 1.70 moles
Divide each mole value by the smallest number of moles calculated. Round to the nearest whole number.
C = 4.76 moles / 0.68 moles = 7
H = 6.10 moles / 0.68 moles = 9
N = 0.68 moles / 0.68 moles = 1
O = 1.70 moles / 0.68 moles = 2.5
Ok so we now have the ratios but for O it's 2.5, have to be whole numbers so we will need to double all the numbers.
C = 14
H = 18
N = 2
O = 5
So the empirical formula is C14H18N2O5
