Answer:
k = 0.086
Step-by-step explanation:
We have the equation
y=ne^(-kt)
where y is the amount of radioactive material after t hours, n is the initial amount of radioactive material, and k is some constant.
We know the following data:
Replacing into the equation and solving for k:
[tex]y=ne^{-kt}[/tex]
[tex]\frac{n}{2}=ne^{-k8}[/tex]
[tex]0.5=e^{-k8}[/tex]
[tex]ln(0.5)=ln(e^{-k8})[/tex]
[tex]ln(0.5)=-k8ln(e)[/tex]
[tex]\frac{ln(0.5)}{-8}=k[/tex]
[tex]\frac{ln(0.5)}{-8}=k[/tex]
[tex]k = 0.086[/tex]
