Respuesta :

Answer:

D. [tex] \frac{7}{12} \: of \: a \: pound[/tex]

Step-by-step explanation:

[tex]total \: candies = 2 \frac{1}{4} + \frac{2}{3} \\ \\ = \frac{9}{4} +\frac{2}{3} \\ \\ = \frac{9 \times 3 + 2 \times 4}{3 \times 4} \\ \\ = \frac{27 + 8}{12} \\ \\ = \frac{35}{12} \\ \\ share \: of \: brother = \frac{1}{5} \times \frac{35}{12} \\ \\ = \frac{7}{12} \: of \: a \: pound[/tex]

Answer:

[tex]\fbox{\begin{minipage}{10em}Option D is correct\end{minipage}}[/tex]

Step-by-step explanation:

Step 1: Let's find the total amount of candy that Loret and her sister have:

Loret has [tex]2\frac{1}{4}[/tex] pound of candy

Loret's sister has [tex]\frac{2}{3}[/tex] pound of candy

=> Total amount: [tex]A =2\frac{1}{4} + \frac{2}{3} = \frac{9}{4} + \frac{2}{3} = \frac{27}{12} + \frac{8}{12} = \frac{35}{12}[/tex] pound of candy

Step 2: Let's find the amount of candy Loret's brother could get:

If Loret's brother did the chores, he can get [tex]\frac{1}{5}[/tex] total amount of candy that Loret and her sister have.

=> The amount Loret's brother can get:

[tex]B = A*\frac{1}{5} = \frac{35}{12} * \frac{1}{5} = \frac{7}{12}[/tex] pound of candy

=> Option D is correct

Hope this helps!

:)