Find the perimeter of a quadrilateral with vertices at C (−1, 2), D (−2, −1), E (2, −2), and F (1, 1). Round your answer to the nearest hundredth when necessary.

PLEASE answer quick, I need this in the next 15 minutes

Respuesta :

Answer:

11.5214512633

Step-by-step explanation:

Add up all the sides, using Pythagorean theorem for each side by finding the difference in horizontal and vertical coordinates.

CD: [tex]\sqrt{\left(2-\left(-1\right)\right)^{2}+\left(\left(-1\right)-\left(-2\right)^{2}\right)}[/tex] = 2

CF: [tex]\sqrt{\left(1-2\right)^{2}+\left(1-\left(-1\right)\right)^{2}}[/tex] = 2.2360679775

EF: [tex]\sqrt{\left(2-1\right)^{2}+\left(-2-1\right)^{2}}[/tex] = 3.16227766017

DE: [tex]\sqrt{\left(2-\left(-2\right)\right)^{2}+\left(\left(-2\right)-\left(-1\right)\right)^{2}}[/tex] = 4.12310562562

add them all up 11.5214512633