Answer:
Length = 80 metres and Width = 60 metres.
Step-by-step explanation:
Given
Length = 90m
Width = 50m
Required
Dimension of another rectangle with the same perimeter but larger area;
Perimeter of a rectangle is calculated as thus;
[tex]Perimeter = 2(Length + Width)[/tex]
Substitute: Length = 90m and Width = 50m
[tex]Perimeter = 2(90m+ 50m)[/tex]
[tex]Perimeter = 2(140m)[/tex]
[tex]Perimeter = 280m[/tex]
Area of a rectangle is calculated as thus;
[tex]Area = Length * Width[/tex]
Substitute: Length = 90m and Width = 50m
[tex]Area = 90m * 50m[/tex]
[tex]Area = 4500m^2[/tex]
So, the implication of this question is to get a rectangle whose perimeter is 280m and area is greater that 4500m²
Using trial by error method;
Assume length of a rectangle is 80m;
This means the width must be 60m
Calculating the perimeter
[tex]Perimeter = 2(80m+ 60m)[/tex]
[tex]Perimeter = 2(140m)[/tex]
[tex]Perimeter = 280m[/tex]
Calculating the area
[tex]Area = 80m * 60m[/tex]
[tex]Area = 4800m^2[/tex]
Since, the area of this rectangle is greater than the area of the previous rectangle. we can adopt this dimension.
Length = 80 metres and Width = 60 metres.
Note: There are other dimensions that have higher area and exact perimeter as the given rectangle in the question;
