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A classic counting problem is to determine the number of different ways that the letters of "misspell" can be arranged. Find that number.

Respuesta :

Answer:

10,080 different ways that the letters of "misspell" can be arranged.

Step-by-step explanation:

Number of arrangents of the letters of a word:

A word has n letters.

The are m repeating letters, each of them repeating [tex]r_{0}, r_{1}, ..., r_{m}[/tex] times

So the number of distincts ways the letters can be arranged is:

[tex]N_{A} = \frac{n!}{r_{1}! \times r_{2}! \times ... \times r_{m}}[/tex]

In this question:

Misspell has 8 letters, with s and l repeating twice.

So

[tex]N_{A} = \frac{8!}{2!2!} = 10080[/tex]

10,080 different ways that the letters of "misspell" can be arranged.