contestada

A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the time after launch. At what time is the height of the ball at its maximum?

Respuesta :

Answer:

The height of the ball is at it's maximum 1.5 units of time after launch.

Step-by-step explanation:

Suppose we have a quadratic function in the following format:

[tex]h(t) = at^{2} + bt + c[/tex]

If t is negative, the maximu value of h(t) will happen at the point

[tex]t_{MAX} = -\frac{b}{2a}[/tex]

In this question:

[tex]h(t) = -25t^{2} + 75t + 24[/tex]

So

[tex]a = -25, b = 75, c = 24[/tex]

Then

[tex]t_{MAX} = -\frac{b}{2a} = -\frac{75}{2*(-25)} = 1.5[/tex]

The height of the ball is at it's maximum 1.5 units of time after launch.

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