Answer:
s(t)=8t
Step-by-step explanation:
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second.
Let the length of the Square = s
[tex]\dfrac{ds}{dt}=8 $cm/seconds, s_0=0 cm[/tex]
We solve the differential equation above subject to the given initial condition.
[tex]\dfrac{ds}{dt}=8\\ds=8$ dt\\Take the integral of both sides\\\int ds=\int 8$ dt\\s(t)=8t+C, where C is the constant of integration\\When t=0, s=0cm\\s(0)=0=8(0)+C\\C=0\\Therefore, s(t)=8t[/tex]
The formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing is:
s(t)=8t (in cm)
