Respuesta :
Answer:
0.902 = 90.2% probability that the flight would leave on time when it is not raining
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Not raining
Event B: Flight leaving on time.
The probability that it will rain is 0.18.
This means that there is a 1 - 0.18 = 0.82 probability of not raining. So [tex]P(A) = 0.82[/tex]
The probability that it will not rain and the flight will leave on time is 0.74.
This means that [tex]P(A \cap B) = 0.74[/tex]
What is the probability that the flight would leave on time when it is not raining?
[tex]P(B|A) = \frac{0.74}{0.82} = 0.902[/tex]
0.902 = 90.2% probability that the flight would leave on time when it is not raining
