Answer:
[tex]\large \boxed{\text{299.4 g}}[/tex]
Explanation:
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 44.10 44.01
C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O
m/g: 100.00
To solve a stoichiometry problem, you must
- Use the molar mass to convert mass of C₃H₈ to moles of C₃H₈
- Use the molar ratio to convert moles of C₃H₈ to moles of CO₂
- Use the molar mass to convert moles of CO₂ to mass of CO₂
1. Moles of C₃H₈
[tex]\text{Moles of C$_{3}$H}_{8} = \text{100.00 g C$_{3}$H}_{8} \times \dfrac{\text{1 mol C$_{3}$H}_{8}}{\text{44.10 g C$_{3}$H}_{8}} = \text{2.268 mol C$_{3}$H}_{8}[/tex]
2. Moles of CO₂
The molar ratio is 3 mol CO₂:1 mol C₃H₈
[tex]\text{Moles of CO}_{2} = \text{2.268 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} = \text{6.803 mol CO}_{2}[/tex]
3. Mass of CO₂
[tex]\text{Mass of CO}_{2} = \text{6.803 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{299.4 g CO}_{2}\\\text{The mass of CO$_{2}$ required is $\large \boxed{\textbf{299.4 g}}$}[/tex]
