Answer:
MN
[tex]= \sqrt{4a^2+4b^2}= 2\sqrt{a^2+b^2}[/tex]
Step-by-step explanation:
From the figure attached,
ΔMON is a right triangle and coordinates of the points M and N are M(0, 2b) and N(2a, 0).
Coordinates of midpoint P → [tex](\frac{2a+0}{2}, \frac{0+2b}{2})[/tex]
From the formula of the distance between two points,
[tex]d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
[tex]\texttt {MN} = \sqrt{(2a-0)^2+(0-2b)^2}\\\\ = \sqrt{4a^2+4b^2}\\\\ = 2\sqrt{a^2+b^2}[/tex]
Similarly, OP
[tex]= \sqrt{(0-a)^2+(0-b)^2}\\\\ = \sqrt{a^2+b^2}[/tex]
Therefore, OP
[tex]= \frac{1}{2}(MN)[/tex]
and MN
[tex]= \sqrt{4a^2+4b^2}= 2\sqrt{a^2+b^2}[/tex]
