Answer:
THE VOLUME OF 32 g OF NO GAS AT 3.12 atm AND 18 °C IS 79.30 L
Explanation:
Mass = 32 g
Pressure = 3.12 atm
Temperature = 18 °C = 18 + 273 K= 291 K
Molar mass of gas NO = (14 + 16) = 30 g/mol
Gas constant = 0.82 L atm mol^-1 K^-1
Volume = unknown
Using PV = nRT where: number of moles = mass / molar mass
PV = m RT / MM
V = mRT / MM P
V = 32 *0.82 * 291 / 30 * 3.21
V = 7635.84 / 96.3
V = 79.30 L
The volume of 32 g NO gas at 3.21 atm and 18 °C is 79.30 L
