Find the value of x. Round to the nearest tenth. Please help!

Answer:
x=88.16349 so 88.2 rounded to the nearest tenth
Step-by-step explanation:
I decided to be different . The angles are 90, 10 and 80 and we know 1 side is 500. I used the law of sines, [tex]\frac{a}{\sin \left(\alpha \right)}=\frac{b}{\sin \left(\beta \right)}=\frac{c}{\sin \left(\gamma \right)}[/tex]
[tex]a=\frac{b\sin \left(α\right)}{\sin \left(β\right)}[/tex]
[tex]A=10^{\circ \:}, B=80^{\circ \:},b=500[/tex]
[tex]x=\frac{500\sin \left(10^{\circ \:}\right)}{\sin \left(80^{\circ \:}\right)}[/tex]
[tex]x=88.16349...[/tex]