Respuesta :
Answer:
Step-by-step explanation:
g(1)=2.2
g(n)=g(n-1)*(-5)
[tex]\frac{g(n)}{g(n-1)}=-5\\so~r=-5\\first term=2.2\\t_{n}=ar^{n-1}\\g(n)=2.2(-5)^{n-1}[/tex]
The nth term of the series is [tex]\rm g(n) = 2.2 ( -5)^{n-1}[/tex].
What is the Common Ratio ?
A common ratio is the ratio of the consecutive terms, it predicts the nature of the series.
The value of g(1) = 2.2
g(n) =g(n-1) * (-5)
The Common Ratio is g(n) /g(n-1) = -5
r = -5
The nth term for a geometric series is given by
[tex]\rm T_n = ar^{n-1}[/tex]
The first term is 2.2
[tex]\rm g(n) = 2.2 ( -5)^{n-1}[/tex]
Therefore, the nth term of the series is [tex]\rm g(n) = 2.2 ( -5)^{n-1}[/tex].
To know more about Common Ratio
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