Answer:
Step-by-step explanation:
Let
[tex]u=\sqrt{x^2+64} \rightarrow du = \frac{x}{\sqrt{x^2+64} }[/tex]
[tex]dv=x^{-2}dx\rightarrow v =-x^{-1}[/tex]
[tex]-x^{-1}\sqrt{x^2+64} |_2^8 +\int\limits^8_2 \frac{1}{\sqrt{x^2+64}} \, dx[/tex]
Apply formula for the integral, replace limits in for the first part.
I believe that you can finish it, right? (all is formula and replace limits in)
