Chlorine dioxide is used as a disinfectant and bleaching agent. In water, it reacts to form chloric acid (HClO3), according to the following balanced equation: 6 ClO2 + 3 H2O → 5 HClO3 + HCl If excess ClO2 is mixed with 18.0 mL of H2O (d = 0.998g/1ml ) how many grams of HClO3 are formed?

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The mass of [tex]\rm HClO_3[/tex] Produced in the reaction has been given by the stoichiometric laws. The mass-produced in the reaction has been 141.03 grams.

What is stoichiometric law?

The stoichiometric law has been the moles produced in the reaction and the reacted equivalent to the stoichiometric coefficient.

The mass of water in the reaction has been given as:

[tex]\rm Density=\dfrac{Mass}{Volume}\\ 0.998\;g/mol=\dfrac{Mass}{18\;ml}\\ Mass=17.964\;grams[/tex]

The molar mass of water has been 18 grams/mol. Thus, 17.964 grams of water has been equivalent to 1 mol.

From the balanced chemical equation, the moles of [tex]\rm HClO_3[/tex] Produced has been given as:

[tex]\rm 3\;mol\;H_2O=5\;mol\;HClO_3\\1\;mol\;H_2O=\dfrac{5}{3}\;\times\;1\;mol\;HClO_3\\ 1\;mol\;H_2O=1.67\;mol\;HClO_3[/tex]

The moles produced has been 1.67 mol. The molar mass of the compound is 84.45 g/mol

The mass can be given as:

[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass\;HClO_3=1.67\;\times\;84.45\;grams\\Mass\;HClO_3=141.03\;grams[/tex]

The  mass of [tex]\rm HClO_3[/tex] Produced in the reaction is 141.03 grams.

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