The length of the smaller rectangle at the right is 1 inch less than twice its width. Both the dimensions of the larger rectangle are 2 inches longer than the smaller rectangle. The area of the shaded region is 86 square inches. What is the area of the larger rectangle? PLEASE its important

Respuesta :

Answer:  464 square inches is the area of the larger rectangle.

Step-by-step explanation:  Assuming that the shaded area is the part of the large rectangle outside the small rectangle, you can set up dimensions from the information given.

The small rectangle's Area = w (2w -1) which is 2w² -w

The large rectangle's Area = (w + 2)(2w + 1) which is 2w² + 5w +2

Now figure out the equation for the "shaded area" (probably outside the small rectangle)  2w² + 5w +2 -(2w² -w) = 86  (The 2w² terms cancel)

6w + 2 = 86,  so 6w = 84, w=14  

Substitute 14 for w in the dimensions of the large rectangle: (w + 2)(2w + 1)

(14+2)(2[14] + 1) = Area

16 × 29 = 464

(I think I deserve Brainliest for figuring this out, but I see the question has been red-flagged, so We'll see!)