The hypotenuse of a 45°-45°-90° triangle measures 18 cm. A right triangle is shown. The other 2 angle measures are 45 degrees. The length of the hypotenuse is 18 centimeters. What is the length of one leg of the triangle? 9 cm 9 StartRoot 2 EndRoot cm 18 cm

Respuesta :

Answer:

[tex]9 \sqrt{2}\ cm[/tex]

Step-by-step explanation:

Given

Hypotenus = 18cm

Required

Find the length of the other two sides

From the question, we understand that the other two sides are equal; let's represent them with x.

Pythagoras theorrem states that:

[tex]Hypotenuse^2 = x^2 + x^2[/tex]

Substitute 18 for Hypotenuse

[tex]18^2 = x^2 + x^2[/tex]

[tex]18^2 = 2x^2[/tex]

[tex]18 * 18 = 2x^2[/tex]

[tex]324 = 2x^2[/tex]

Divide both sides by 2

[tex]\frac{324}{2} = \frac{2x^2}{2}[/tex]

[tex]162 = x^2[/tex]

Take root of both sides

[tex]\sqrt{162} = \sqrt{x^2}[/tex]

[tex]\sqrt{162} = x[/tex]

[tex]x = \sqrt{162}[/tex]

[tex]x = \sqrt{81 * 2}[/tex]

Split the above

[tex]x = \sqrt{81} *\sqrt{2}[/tex]

[tex]x = 9 *\sqrt{2}[/tex]

[tex]x = 9 \sqrt{2}[/tex]

Hence, the length of one leg is [tex]9 \sqrt{2}\ cm[/tex]

Answer:

B: 9 square root 2 cm

Step-by-step explanation:

This is correct on edge 2020