Answer:
mBC = 96°
mB = 55°
mC = 77°
mAB = 154°
Step-by-step explanation:
The angle mB inscribes the arc mAC, so we have:
[tex]mB = mAC / 2[/tex]
[tex]mB = 110 / 2 = 55\°[/tex]
The sum of internal angles of a triangle is 180°, so in the triangle ABC we have:
[tex]mA + mB + mC = 180[/tex]
[tex]48 + 55 + mC = 180[/tex]
[tex]mC = 180 - 48 - 55[/tex]
[tex]mC = 77\°[/tex]
Using again the property of inscribed angles, we have:
[tex]mAB = 2*mC = 154\°[/tex]
[tex]mBC = 2*mA = 96\°[/tex]
