Answer:
a = 3, b = 5
Step-by-step explanation:
Given
x² - 6x + 4 = 0 ( subtract 4 from both sides )
x² - 6x = - 4
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = - 4 + 9
(x - 3)² = 5 ( take the square root of both sides )
x - 3 = ± [tex]\sqrt{5}[/tex] ( add 3 to both sides )
x = 3 ± [tex]\sqrt{5}[/tex] ← in the form a ± [tex]\sqrt{b}[/tex]
with a = 3 and b = 5
