Answer:
[tex]392\pi \: {in}^{3} [/tex]
solution,
radius=7 in
Slant height=25 in
[tex]h = \sqrt{ {(slant \: height}^{2} - {(radius)}^{2} } \\ = \sqrt{ {(25)}^{2} - {(7)}^{2} } \\ = \sqrt{625 - 49} \\ = \sqrt{576} \\ = \sqrt{ {(24)}^{2} } \\ = 24 \: in[/tex]
Volume of cone:
[tex] \frac{1}{3} \pi \: {r}^{2} h \\ = \frac{1}{3} \times \pi \times {(7)}^{2} \times 24 \\ = \frac{1}{3} \times \pi \times 49 \times 24 \\ = 392\pi \: {in}^{3} [/tex]
hope this helps...
Good luck on your assignment...
