Answer:
The answer is given below
Step-by-step explanation:
Let the number of passengers that boarded the bus at the interchange be x.
At the first bus stop, 1/4 of the passengers alighted the bus and 6 people boarded the bus.
Therefore The number of passengers when the bus left the first bus stop = [tex]x-\frac{1}{4}x +6=\frac{3}{4}x+6[/tex]
At the 2nd bus stop, 8/15 of the passengers alighted and 10 passengers boarded the bus.
Therefore The number of passengers when the bus left the second bus stop
[tex]=\frac{3}{4}x+6-\frac{8}{15}( \frac{3}{4}x+6)+10=\frac{3}{4}x+6-\frac{8}{20}x-3.2+10\\\\=\frac{7}{20}x+12.8[/tex]
Given that there were 24 passengers on the bus when it left the 2nd bus stop
[tex]\frac{7}{20}x+12.8=24\\7x+256=480\\7x=480-256\\7x=224\\x=32[/tex]
Therefore 32 passengers boarded the bus at the interchange
