Answer:
Replace
/*Your solution goes here*/
with
GetUserInfo(&userAge, userName);
And Modify:
printf("%s is %d years old.\n", userName, userAge)
to
printf("%s is %d years old.", &userName, userAge);
Explanation:
The written program declares userAge as pointer;
This means that the variable will be passed and returned as a pointer.
To pass the values, we make use of the following line:
GetUserInfo(&userAge, userName);
And to return the value back to main, we make use of the following line
printf("%s is %d years old.", &userName, userAge);
The & in front of &userAge shows that the variable is declared, passed and returned as pointer.
The full program is as follows:
#include <stdio.h>
#include <string.h>
void GetUserInfo(int* userAge, char userName[]) {
printf("Enter your age: ");
scanf("%d", userAge);
printf("Enter your name: ");
scanf("%s", userName);
return;
}
int main(void) {
int* userAge = 0;
char userName[30] = "";
GetUserInfo(&userAge, userName);
printf("%s is %d years old.", &userName, userAge);
return 0;
}
