Respuesta :
Answer:
Multiply the first equation by 3
Multiply the second equation by -7
Step-by-step explanation:
After doing the above method, you will derive equation 3 and 4 then you can eliminate the x and get y .
FURTHER EXPLANATION
[tex]-7x + 2y = 5 -------(1)\\3x - 5y = -5-------(2)\\\\-7x + 2y = 5 -------(1) \times 3\\3x - 5y = -5-------(2)\times-7\\\\-21x +6y=15 -----(3)\\-21x +35y=35----(4)\\Subtract -eq- 4- from -eq- 3 \\-29y =-20\\Divide-both-sides-by;-29\\\frac{-29y}{-29} =\frac{-20}{-29} \\y = 20/29\\[/tex]
[tex]Substitute ; 20/29 for y- in- eq 1\\-7x + 2y = 5----(1)\\-7x +2(20/29) = 5\\-7x +40/29=5\\-7x = 5 - 40/29\\-7x = 105/29\\Divide through by -7\\x = -15/29[/tex]
I Hope It helps
Answer:
Multiply the first equation by 3
Multiply the second equation by -7
Step-by-step explanation:
[tex] ( - 7x + 2y = 5) \times 3 \\ (3x - 5y = - 5) \times 7[/tex]
[tex] - 21x + 6y = 15 ..(3)\\ - 21x - 35y = - 35...(4)[/tex]
Subtract equation 3 from equation 4
[tex] - 21x - ( - 21x) = - 21x + 21x = 0[/tex]
x has been eliminated