Respuesta :
Answer:
B) 0.894
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
A local animal rescue organization receives an average of 0.55 rescue calls per hour.
This means that [tex]\mu = 0.55[/tex]
Probability that during a randomly selected hour, the organization will receive fewer than two calls.
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577[/tex]
[tex]P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894[/tex]
