Answer:
[tex] \boxed{\sf (8x + y)(2x + 3y)} [/tex]
Step-by-step explanation:
[tex] \sf Factor \: the \: following: \\ \sf \implies {(5x + 2y)}^{2} - {( 3x - y)}^{2} \\ \\ \sf Factor \: the \: difference \: of \: two \: squares. \\ \sf {(5x + 2y)}^{2} - (3x - y)^{2} = ((5x + 2y) + (3x - y)) \\ \sf ((5x + 2y) - (3x - y)) : \\ \sf \implies ((5x + 2y) + (3x - y))((5x + 2y) - (3x - y)) \\ \\ \sf Grouping \: like \: terms, \: 5x + 2y + 3x - y = \\ \sf (5x +3x) + (2y - y) : \\ \sf \implies \boxed{ \sf( (5x +3x) + (2y - y))}((5x + 2y) - (3x - y) \\ \\ \sf 5x + 3x = 8x : \\ \sf \implies (\boxed{ \sf 8x} + (2y - y))((5x + 2y) - (3x - y)) \\ \\ \sf 2y - y = y : \\ \sf \implies (8x + \boxed{ \sf y})((5x + 2y) - (3x - y)) \\ \\ \sf - (3x-y)=y-3x: \\ \sf \implies (8x + y)(5x + 2y + \boxed{ \sf y - 3x}) \\ \\ \sf Grouping \: like \: terms, \: 5x + 2y + y - 3x = \\ \sf (5x - 3x)(2y + y) : \\ \sf \implies (8x + y) + \boxed{ \sf ((5x - 3x)(2y + y))} \\ \\ \sf 5x - 3x = 2x : \\ \sf \implies (8x + y)( \boxed{ \sf 2x} + (2y + y)) \\ \\ \sf 2y + y = 3y : \\ \sf \implies (8x + y)(2x + \boxed{ \sf 3y})[/tex]
