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The center of a bar magnet whose magnetic dipole moment is <6,0,0> A·m2 is located at the origin. A second bar magnet whose magnetic dipole moment is <7, 0, 0> A·m2 is located at 0.23 m. What is the vector force on the second magnet due to the first magnet? (Express your answer in vector form.)

Respuesta :

Complete Question

The complete question is shown on the first uploaded image

Answer:

The force is  [tex]\= F = (-0.001089, 0 ,0)[/tex]

Explanation:

From the question we are told that

      The magnetic dipole moment of first magnet  is  [tex]z_1 = (6,0,0) A \cdot m^2[/tex]

       The magnetic dipole moment of second magnet  is  [tex]z_2 = (7,0,0) A \cdot m^2[/tex]

       The location of the second magnetic dipole moment is  [tex]x = 0.39 \ m[/tex]

Generally the vector force on the second magnet due to the first is mathematically evaluated as

         [tex]\= F =- \frac{\mu_o }{4 \pi} * \frac{6 * z_1 * z_2}{x^4}[/tex]

Where  [tex]\mu _o[/tex] is the permeability of free space with value  [tex]4\pi * 10^{-7} N/A^2[/tex]

substituting values

            [tex]\= F = - \frac{ 4\pi * 10^{-7} }{4 \pi} * \frac{6 * 6 * 7}{0.39^4}[/tex]

           [tex]\= F = (-0.001089, 0 ,0)[/tex]

Note the negative sign show that the force is an attraction force

Ver imagen okpalawalter8