Answer:
The z–score corresponding to 45 is z=2.
Step-by-step explanation:
We have a random variable X represented by a normal distribution, with mean 35 and standard deviation 5.
The z-score represents the value X relative to the standard normal distribution. This allows us to calculate probabilities for any given normal distribution with the same table.
The z-score for X=45 can be calculated as:
[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{45-35}{5}=\dfrac{10}{5}=2[/tex]
The z–score corresponding to 45 is z=2.