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Suppose that the voltage of the battery in the circuit is 3.9 V, the magnitude of the magnetic field (directed perpendicularly into the plane of the paper) is 1.1 T, and the length of the rod between the rails is 0.22 m. Assuming that the rails are very long and have negligible resistance, find the maximum speed attained by the rod after the switch is closed.

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mavila18

Answer:

v = 16.11 m/s

Explanation:

In order to calculate the maximum speed of the rod, you use the following formula:

[tex]\epsilon=vBLsin\theta[/tex]        (1)

ε = voltage of the circuit = 3.9V

v: maximum speed of the rod = ?

B: magnitude of the magnetic field = 1.1T

L: length of the rod = 0.22m

θ: angle between the direction of motion of the rod and the direction of the magnetic field = 90°

You solve the equation (1) for v and replace the values of the other parameters:

[tex]v=\frac{\epsilon}{BLsin\theta}=\frac{3.9V}{(1.1T)(0.22m)sin90\°}\\\\v=16.11\frac{m}{s}[/tex]

The maximum speed of the rod is 16.11 m/s

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