Answer:
Step-by-step explanation:
To find the size of YXZ we should use some trigonometry but first let's find the length of YZ
- The Pythagorian theorem :
(XZ)²+(ZY)²=(YX)²
YX=[tex]\sqrt{20^{2}+8^{2} }[/tex]
=4[tex]\sqrt{29}[/tex]
We khow that sin(YXZ)=(YZ)/(YX)
= 20/(4[tex]\sqrt{29}[/tex])
= 5/[tex]\sqrt{29}[/tex]
- using a calculator we get (YXZ)= 68°
