Answer:
0.93L
Explanation:
Hello,
To solve this question, we need to first of all write down the equation of reaction.
Equation of reaction,
2Mg + 4HCl → 2MgCl₂ + 2H₂
From the equation of reaction, it shows that 2 moles of Mg produces 2 moles of H₂.
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Molar mass of Mg = 24g/mol
Mass = 2 × 24 = 48g
Therefore, 48g of Mg produces (2 × 22.4)L of H₂
48g of Mg = 44.8L of H₂
1g of Mg = xL of H₂
x = (1 × 44.8) / 48
x = 0.93L
1g of Mg will produce 0.93L of H₂
