Answer:
MgO
Explanation:
The following data were obtained from the question:
mass of crucible and cover + magnesium metal = 33.741 g
mass of crucible and cover = 33.5 g
mass of crucible and cover + magnesium oxide = 33.899 g
Next, we shall determine the mass of magnesium metal. This can be obtained as follow:
mass of crucible and cover + magnesium metal = 33.741 g
mass of crucible and cover = 33.5 g
Mass of magnesium metal =..?
Mass of magnesium metal = (mass of crucible and cover + magnesium metal) – (mass of crucible and cover)
Mass of magnesium metal = 33.741 – 33.5
Mass of magnesium metal = 0.241g
Next, we shall determine the mass of magnesium oxide. This can be obtained as follow:
mass of crucible and cover + magnesium oxide = 33.899 g
mass of crucible and cover = 33.5 g
Mass of magnesium oxide =?
Mass of magnesium oxide = (mass of crucible and cover + magnesium oxide) – (mass of crucible and cover)
Mass of magnesium oxide = 33.899 –. 33.5
Mass of magnesium oxide = 0.399g
Next, we shall determine the mass of oxygen. This can be obtained as follow:
Mass of magnesium oxide = 0.399g
Mass of magnesium metal = 0.241g
Mass of oxygen =..?
Mass of oxygen = (Mass of magnesium oxide) – (Mass of magnesium metal)
Mass of oxygen = 0.399 – 0241
Mass of oxygen = 0.158g
Now, we can obtain the empirical formula for the magnesium oxide as follow:
Mg = 0.241g
O = 0.158g
Divide by their molar mass
Mg = 0.241 / 24 = 0.01
O = 0.158 / 16 = 0.0099
Divide by the smallest
Mg = 0.01 / 0.0099 = 1
O = 0.0099 / 0.0099 = 1
Therefore, the empirical formula for the magnesium oxide is MgO
