Answer:
[tex]\boxed{\text{472 K}}[/tex]
Explanation:
The volume and number of moles are constant, so we can use Gay-Lussac’s Law:
At constant volume and number of particles, the pressure exerted by a gas is directly proportional to its temperature.
[tex]\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}[/tex]
Data:
p₁ = 0.500 atm; T₁ = 315 K
p₂ = 0.750 atm; T₂ = ?
Calculations:
[tex]\begin{array}{rcl}\dfrac{0.500}{0.750} & = & \dfrac{315}{T_{2}}\\\\0.6667 & = & \dfrac{315}{T_{2}}\\\\0.6667T_{2} & = & 315\\\\T_{2} & = &\dfrac{315}{0.6667}\\\\ & = &\textbf{472 K}\\\end{array}\\\text{The new temperature of the gas is }\boxed{\textbf{472 K}}[/tex]
